Solutions of Homework Set # 2: [1] [2] [3]
Solutions of Set # 3: [1] [2] [3]
Notice that there is a typo in the solution of 2b). The last formula should read: u +\frac {d^2}du^2} = + \frac m{L_z^2u^2} f(1/u). Then the sign on the first formula of the solution of 2c) is also opposite, and contrary to an earlier comment, k > 0. The sign of the term with k in the 4, 5, and 6th line should also be opposite. The final result is correct, i.e. \frac{d^2\dleta u}{d\phi^2} = -\delta u (n+3).
Solutions of Set # 4: [1] [2] [3] [4] [5]
Solutions of Set # 5: [1] [2] [3] [4] [5] [6] [7] [8] [9]
The initial conditions in 3) should read x(0) = 0, x'(0) = 0.
In problem 3b) the Ansatz should read: x = A t \sin \omega t + b \cos\3\omega t.
The idea of problem 4) is that you first calculate the period from integrating \frac{dx}{dt } = \sqrt{2(E-V)} sp that \be T = 2 \int \frac{dx}{\qsrt{2(E-V)} \ee and the integral over $x$ is inbetween the turning points, which depend on $\epsilon$. You can expand this formula to first order in \epsilon. the result should agree with LL.
Solutions of Set # 7: [1] [2] [3] [4] [5]
Solutions of Set # 8: [1] [2] [3] [4] [5]
Solutions of Set # 9: [1] [2] [3] [4]
Solutions of Set # 10: [1] [2] [3] [4] [4]
There is a typo in eq. (1). The first "=" sign should read "+".
Solutions of Set # 11: [1] [2] [3] [4]
Problem 3 is computational and no solution is given.
Notice the new due date because you have the quantum mechanics final one week before its scheduled date.